Question

1)(x+6)(x-3)=0 2)x(x+3,5)(4,8-x)=0

Answer 1

Ответ:

Пошаговое объяснение:

1)х1=-6 х2=3

2)х1=-3,5 х2=0 х3=24/5

Answer 2

To find the solutions for the given equations, you can set each factor equal to zero and solve for $x$.

1) $(x + 6)(x - 3) = 0$

Setting each factor equal to zero gives you two equations:

$x + 6 = 0$ or $x - 3 = 0$

Solving these equations, you get:

$x = -6$ or $x = 3$

So, the solutions for the first equation are $x = -6$ and $x = 3$.

2) $x(x + 3.5)(4.8 - x) = 0$

Setting each factor equal to zero gives you three equations:

$x = 0$, $x + 3.5 = 0$ or $4.8 - x = 0$

Solving these equations, you get:

$x = 0$, $x = -3.5$ or $x = 4.8$

So, the solutions for the second equation are $x = 0$, $x = -3.5$ and $x = 4.8$.