Question

1) (9х-4)+(15х-5)=18-(25-22х) 2) (10х+6)-(9-9х)+(8-11х)=-193) 7(х-1)-3(2х+1)=-х-154) (х^2+4x-8)-(7x-2x^2-5)=3x^2-(4x+4)​

Answer 1

1)

(9х-4)+(15х-5)=18-(25-22х)

9х-4+15х-5=18-25+22х

9х+15х-22х=18-25+5+4

2х=2

х=2/2

х=1

2)

(10х+6)-(9-9х)+(8-11х)=-19

10х+6-9+9х+8-11х=-19

10x+9x-11x=-19-8+9-6

8x=-24

x=-24/8

x=-3

3)

7*(х-1)-3*(2х+1)=-х-15

7x-7-6x-3=-x-15

7x-6x+x=-15+3+7

2x=-5

x=-5/2

x=-2,5

4)

(x²+4x-8)-(7x-2x²-5)=3x²-(4x+4)

x²+4x-8-7x+2x²+5=3x²-4x-4

x²+2x²+4x-7x-8+5=3x²-4x-4

3x²-3x-3=3x²-4x-4

3x²-4x-4=3x²-3x-3

3x²-4x-3x²+3x=-3+4

3x²-3x²-4x+3x=-3+4

-1x=1

x=1/(-1)

x=-1

Answer 2

Let's solve each of these equations step by step:

1. (9x - 4) + (15x - 5) = 18 - (25 - 22x)

First, simplify both sides of the equation:

24x - 9 = 18 - 25 + 22x

Now, move like terms to the same side of the equation:

24x - 22x = 18 - 25 + 9

2x = 2

Now, divide both sides by 2 to isolate x:

x = 2/2

x = 1

So, the solution to the first equation is x = 1.

2. (10x + 6) - (9 - 9x) + (8 - 11x) = -19

First, simplify both sides of the equation:

10x + 6 - 9 + 9x + 8 - 11x = -19

Now, combine like terms:

(10x + 9x - 11x) + (6 - 9 + 8) = -19

(8x - 19) = -19

Now, add 19 to both sides of the equation to isolate x:

8x = 0

Finally, divide both sides by 8 to find the value of x:

x = 0

So, the solution to the second equation is x = 0.

3. 7(x - 1) - 3(2x + 1) = -x - 15

Let's distribute the constants:

7x - 7 - 6x - 3 = -x - 15

Now, combine like terms:

(7x - 6x + x) - 7 - 3 = -15

2x - 10 = -15

Now, add 10 to both sides of the equation to isolate x:

2x = -5

Finally, divide both sides by 2 to find the value of x:

x = -5/2

So, the solution to the third equation is x = -5/2.

4. (x^2 + 4x - 8) - (7x - 2x^2 - 5) = 3x^2 - (4x + 4)

Let's simplify both sides of the equation step by step:

x^2 + 4x - 8 - 7x + 2x^2 + 5 = 3x^2 - 4x - 4

Now, combine like terms on both sides:

(1x^2 + 2x^2 + 3x^2) + (4x + 7x + 4x) + (-8 + 5) = -4

6x^2 + 15x - 3 = -4

Now, add 4 to both sides of the equation to isolate the terms with x:

6x^2 + 15x - 3 + 4 = 0

6x^2 + 15x + 1 = 0

Now, you can solve this quadratic equation using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 6, b = 15, and c = 1. Plug these values into the quadratic formula:

x = (-15 ± √(15^2 - 4(6)(1))) / (2(6))

x = (-15 ± √(225 - 24)) / 12

x = (-15 ± √201) / 12

So, the solutions to the fourth equation are x = (-15 + √201)/12 and x = (-15 - √201)/12.