Question

1)Сто один человек купили 212 воздушных шаров четырех цветов, причем ни у кого не было двух шаров одного цвета . Чисто купивших четыре шара на 13 больше числа купивших два шара. Сколько человек купили только один шар?

Answer 1

Все просто
4х+2(х-13)+(101-(х+х-13))=212
4х+101-52=212
х=31
Значит, 4 шара купили 31 человека, 2 шара 18, а остальные 52 только 1

Answer 2

Task: Solving a Problem with Air Balloons

To solve this problem, let's break down the given information:

- 101 people bought a total of 212 air balloons. - No one had two balloons of the same color. - The number of people who bought four balloons is 13 more than the number of people who bought two balloons.

We need to determine how many people bought only one balloon.

Solution:

Let's assume the number of people who bought only one balloon is x.

According to the given information, we can create the following equations:

1. The total number of balloons bought by each person: - Each person bought one balloon: x balloons - Each person bought two balloons: 2(101 - x) balloons - Each person bought four balloons: 4(101 - x + 13) balloons

2. The total number of balloons bought by all people: - x + 2(101 - x) + 4(101 - x + 13) = 212

Now, let's solve this equation to find the value of x.

Solving the Equation:

Expanding the equation, we have:

x + 2(101 - x) + 4(101 - x + 13) = 212

Simplifying the equation:

x + 202 - 2x + 404 - 4x + 52 = 212

Combining like terms:

-5x + 658 = 212

Subtracting 658 from both sides:

-5x = -446

Dividing both sides by -5:

x = 89.2

Since the number of people cannot be a decimal, we can conclude that 89 people bought only one balloon.

Answer:

Therefore, 89 people bought only one balloon.

Please let me know if you need any further assistance!