Question

A) 4(x + 3) = 5(x - 2); 6) -2(x - 5) + 3(x - 4) = 4x + 1;B) 3(x - 1) = 2(x + 2);r) 3(x - 5) - 2(x + 4) = -5x + 1.​

Answer 1

Ответ:

Пошаговое объяснение:

а) 4(х+3)=5(х–2)

4х+12=5х–10

4х–5х= –10–12

–х= –22

х=22

б) –2(х–5)+3(х–4)=4х+1

–2х+10+3х–12=4х+1

х–4х=1+12–10

–3х=3

х=3÷(–3)

х= –1

в) 3(х–1)=2(х+2)

3х–3=2х+4

3х–2х=4+3

х=7

г) 3(х–5)–2(х+4)= –5х+1

3х–15–2х–8= –5х+1

х+5х=1+15+8

6х=24

х=24÷6

х=4

Answer 2

Let's solve these equations step by step:

A) 4(x + 3) = 5(x - 2)

First, distribute the constants on both sides of the equation:

4x + 12 = 5x - 10

Now, isolate the variable terms on one side and constants on the other side:

4x - 5x = -10 - 12

-x = -22

Now, divide both sides by -1 to solve for x:

x = 22

So, the solution to equation A) is x = 22.

6. -2(x - 5) + 3(x - 4) = 4x + 1

First, distribute the constants on both sides of the equation:

-2x + 10 + 3x - 12 = 4x + 1

Now, combine like terms:

(3x - 2x) + (10 - 12) = 4x + 1

x - 2 = 4x + 1

Now, isolate the variable terms on one side and constants on the other side:

x - 4x = 1 + 2

-3x = 3

Now, divide both sides by -3 to solve for x:

x = -1

So, the solution to equation 6) is x = -1.

B) 3(x - 1) = 2(x + 2)

First, distribute the constants on both sides of the equation:

3x - 3 = 2x + 4

Now, isolate the variable terms on one side and constants on the other side:

3x - 2x = 4 + 3

x = 7

So, the solution to equation B) is x = 7.

r) 3(x - 5) - 2(x + 4) = -5x + 1

First, distribute the constants on both sides of the equation:

3x - 15 - 2x - 8 = -5x + 1

Now, combine like terms:

(3x - 2x) - (15 + 8) = -5x + 1

x - 23 = -5x + 1

Now, isolate the variable terms on one side and constants on the other side:

x + 5x = 1 + 23

6x = 24

Now, divide both sides by 6 to solve for x:

x = 4

So, the solution to equation r) is x = 4.