Question

1)3(4-x)+1=2(3-x)+6; 2)(5-3x)-(7-2x)=-3-2x; 3)2x-19=8-x; 4)11-6x=31-10x

Answer 1

Ответ:

1)3(4-x)+1=2(3-x)+6

12-3х+1=6-2х+6

-3х+2х=12-12-1

-х=-1

х=1

2)(5-3x)-(7-2x)=-3-2x

5-3х-7+2х=-3-2х

-х+2х=-3+7-5

х=-1

3)2x-19=8-x

2х+х=8+19

3х=27

х=9

4)11-6x=31-10x

-6х+10х=31-11

4х=20

х=5

Пошаговое объяснение:

Answer 2

Sure, I can help you solve these equations:

1. 3(4-x) + 1 = 2(3-x) + 6

First, distribute the constants:

12 - 3x + 1 = 6 - 2x + 6

Now, simplify:

12 - 3x + 1 = 12 - 2x

Next, move terms involving x to one side of the equation and constants to the other side:

-3x + 1 + 2x = 12 - 12

Now, combine like terms:

-x + 1 = 0

Now, isolate x by moving 1 to the other side:

-x = -1

Finally, multiply both sides by -1 to solve for x:

x = 1

So, the solution to the first equation is x = 1.

2. (5-3x) - (7-2x) = -3 - 2x

First, remove the parentheses by distributing the negative sign on the second term:

5 - 3x - 7 + 2x = -3 - 2x

Now, simplify:

-2x - 2 = -3 - 2x

Notice that the terms involving x cancel out. This means that this equation doesn't have a unique solution. It's an identity, which means any value of x will satisfy it.

So, for equation 2, there are infinitely many solutions, and any value of x will work.

3. 2x - 19 = 8 - x

First, add x to both sides to move terms involving x to one side:

2x + x - 19 = 8

Now, combine like terms:

3x - 19 = 8

Next, move the constant term -19 to the other side by adding 19 to both sides:

3x - 19 + 19 = 8 + 19

Simplify:

3x = 27

Now, divide both sides by 3 to solve for x:

3x/3 = 27/3

x = 9

So, the solution to the third equation is x = 9.

4. 11 - 6x = 31 - 10x

First, add 6x to both sides to move terms involving x to one side:

11 = 31 - 10x + 6x

Now, simplify:

11 = 31 - 4x

Next, move the constant term 31 to the other side by subtracting 31 from both sides:

11 - 31 = -4x

Simplify:

-20 = -4x

Now, divide both sides by -4 to solve for x:

(-20)/(-4) = (-4x)/(-4)

5 = x

So, the solution to the fourth equation is x = 5.