Question

А+b+c=12.2a+2b+3c=31 2C. =? ​

Answer 1

Ответ:

7

Пошаговое объяснение:

а+b+c=12.

2a+2b+3c=31

а+b=12-с

2*(а+b)+3с=31

Объединяем:

2*(12-с)+3с=31

24-2с+3с=31

24+с=31

с=31-24

с=7

Answer 2

To solve this system of equations for the variable "c," you can use either substitution or elimination method. I'll use the elimination method here:

Given equations:

1. A + b + c = 12.2
2. 2a + 2b + 3c = 31

First, let's multiply the first equation by 2 to make the coefficients of "b" in both equations equal:

2(A + b + c) = 2(12.2)

This simplifies to:

2A + 2b + 2c = 24.4

Now, we can subtract the first equation from the second equation to eliminate "b" and solve for "c":

(2A + 2b + 3c) - (2A + 2b + 2c) = 31 - 24.4

This simplifies to:

c = 6.6

So, the value of "c" is 6.6.