Question

15(2-x)+1<6(2x-1)-10(2x-3)

Answer 1

Ответ:

$x$∈(1;+∞)

Пошаговое объяснение:

$15(2-x)+1$

$x$∈(1;+∞)

Answer 2

To solve the inequality $15(2-x) + 1 < 6(2x - 1) - 10(2x - 3)$, let's follow these steps:

1. Distribute and simplify both sides of the inequality: $30 - 15x + 1 < 12x - 6 - 20x + 30$.

2. Combine like terms on both sides: $-15x + 31 < -8x + 24$.

3. Move the variable terms to one side and constants to the other: $-15x + 8x < 24 - 31$.

4. Simplify the left side: $-7x < -7$.

5. Divide both sides by $-7$, remembering to reverse the inequality sign when dividing by a negative number: $x > 1$.

So the solution to the inequality $15(2-x) + 1 < 6(2x - 1) - 10(2x - 3)$ is $x > 1$.