Question

1 1/2+(-17 2/5)+12 3/4=

Answer 1

$1\frac{1}{2}+(-17\frac{2}{5})+12\frac{3}{4}=\frac{3}{2}-17\frac{2}{5}+\frac{51}{4}=\frac{3}{2}-\frac{87}{5}+\frac{51}{4}=-\frac{63}{20}=-3,15$

Answer 2

Ответ:

3/2 - 17 ⅖ + 51/4

3/2 - 87/5 +51/4= - 63/20

Answer 3

To solve the expression $1 \frac{1}{2} + (-17 \frac{2}{5}) + 12 \frac{3}{4}$, we'll follow these steps:

1. Convert all the mixed numbers to improper fractions.
2. Perform the addition.

Let's do it step by step:

1. $1 \frac{1}{2}$ as an improper fraction is $\frac{3}{2}$ because $1 \frac{1}{2} = \frac{2 \cdot 1 + 1}{2} = \frac{3}{2}$.

2. $-17 \frac{2}{5}$ as an improper fraction is $-\frac{87}{5}$ because $-17 \frac{2}{5} = -\frac{5 \cdot 17 + 2}{5} = -\frac{87}{5}$.

3. $12 \frac{3}{4}$ as an improper fraction is $\frac{51}{4}$ because $12 \frac{3}{4} = \frac{4 \cdot 12 + 3}{4} = \frac{51}{4}$.

Now, we can substitute these values back into the original expression:

$\frac{3}{2} - \frac{87}{5} + \frac{51}{4}$

Next, we need to find a common denominator. In this case, the common denominator will be $2 \cdot 5 \cdot 4 = 40$.

Now, let's rewrite the fractions with the common denominator:

$\frac{3 \cdot 20}{2 \cdot 20} - \frac{87 \cdot 8}{5 \cdot 8} + \frac{51 \cdot 10}{4 \cdot 10}$

$= \frac{60}{40} - \frac{696}{40} + \frac{510}{40}$

Now, we can perform the addition:

$= -\frac{36}{40}$

Finally, we can simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 4:

$= -\frac{9}{10}$

So, $1 \frac{1}{2} + (-17 \frac{2}{5}) + 12 \frac{3}{4} = -\frac{9}{10}$.