Question

Д) 9*9-540:(a-27)=15*5Е)80*b-3*90+430=1600:2​

Answer 1

Ответ:

а) 117

б) 8

Надеюсь в картинке всё понятно

Answer 2

To solve the given equations for $a$ and $b$, let's follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction):

For equation D: $9 \times 9 - \frac{540}{a - 27} = 15 \times 5$

1. First, let's simplify the right-hand side: $15 \times 5 = 75$

2. Now, rewrite the equation: $81 - \frac{540}{a - 27} = 75$

3. Subtract 81 from both sides: $- \frac{540}{a - 27} = -6$

4. Now, let's isolate $a$ by multiplying both sides by $-(a - 27)$ (be careful with the signs): $540 = -6(a - 27)$

5. Divide both sides by $-6$: $-90 = a - 27$

6. Add 27 to both sides to solve for $a$: $a = -90 + 27 = -63$

So, $a = -63$.

For equation E: $80b - 3 \times 90 + 430 = \frac{1600}{2}$

1. Simplify the right-hand side: $80b - 270 + 430 = 800$

2. Combine the constants: $80b + 160 = 800$

3. Now, isolate $b$ by subtracting 160 from both sides: $80b = 640$

4. Divide both sides by 80 to solve for $b$: $b = \frac{640}{80} = 8$

So, $b = 8$.