Question

(x²-x-1)(y+2)+(1+x-x²)(z+12)

Answer 1

Ответ: x²(z-10) - y - 14.

Пошаговое объяснение: Выполним умножение:

(x²-x-1)(y+2)+(1+x-x²)(z+12) =

= xy + 2x² - xy -2x -y - 2 + xz + 12 + x - x²z - 12x² - x + x² =

= -12x² + 2x² + x²z + xy - xy + xz - x + x - y + 12 - 2 =

= x²(z-10) - y - 14.

Ответ: x²(z-10) - y - 14.

Answer 2

To simplify the given expression $(x^2 - x - 1)(y + 2) + (1 + x - x^2)(z + 12)$, we'll first expand each term and then combine like terms:

Expanding the first term: $(x^2 - x - 1)(y + 2) = xy + 2x - xy - 2x - y - 2$.

Simplifying the first term: $xy - xy + 2x - 2x - y - 2$.

Simplifying further: $-y - 2$.

Expanding the second term: $(1 + x - x^2)(z + 12) = z + 12 + xz + 12x - x^2z - x^2 \cdot 12$.

Simplifying the second term: $z + 12 + xz + 12x - x^2z - 12x^2$.

Now, let's combine the simplified terms: $(-y - 2) + (z + 12 + xz + 12x - x^2z - 12x^2)$.

Rearranging and combining like terms: $xz - x^2z + 12x - y + z - 2 - 12x^2 + 12$.

Finally, the simplified expression is: $xz - x^2z + 12x - y + z - 2 - 12x^2 + 12$