Question

1) (x +26)12 = 360;2) (132-x): 4 = 23;3) 5(2x +27) = 405;​

Answer 1

Пошаговое объяснение:

вот!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

To solve the given equations, we'll go through each one step by step and find the value of $x$ for each equation.

1. $(x + 26) \times 12 = 360$

First, let's isolate $x$ by dividing both sides by 12:

$x + 26 = \frac{360}{12}$ $x + 26 = 30$

Now, subtract 26 from both sides to find $x$:

$x = 30 - 26$ $x = 4$

2. $\frac{132 - x}{4} = 23$

First, let's multiply both sides by 4 to isolate $132 - x$:

$132 - x = 23 \times 4$ $132 - x = 92$

Now, subtract 132 from both sides to find $x$:

$-x = 92 - 132$ $-x = -40$

Finally, multiply both sides by -1 to find $x$:

$x = 40$

3. $5(2x + 27) = 405$

First, let's distribute 5 to both terms inside the parentheses:

$10x + 135 = 405$

Now, isolate $x$ by subtracting 135 from both sides:

$10x = 405 - 135$ $10x = 270$

Finally, divide both sides by 10 to find $x$:

$x = \frac{270}{10}$ $x = 27$