Question

(4 5/13+2 8/13) - (1 12/13+3 7/13)

Answer 1

В ПЕРВЫХ СКОБКАХ ПОЛУЧАЕТСЯ 7 А ВО ВТОРОЙ ПОЛУЧАЕТСЯ 5 6/13  А ВСЕГО ОТВЕТ 1 7/13 DJN ВОТ ВСЕ

Answer 2

$(4 \frac{5}{13} +2 \frac{8}{13}) -(1 \frac{12}{13} +3 \frac{7}{13})= 6 \frac{13}{13} -4 \frac{19}{13}=6 \frac{13}{13}-5 \frac{6}{13} =1 \frac{7}{13}$

Answer 3

To subtract the two mixed numbers, you can follow these steps:

Step 1: Add or subtract the fractions separately. Step 2: Add or subtract the whole numbers separately. Step 3: Combine the results from Steps 1 and 2.

Let's do the calculations:

For the first mixed number: $4 \frac{5}{13} + 2 \frac{8}{13}$

Step 1: Add the fractions: $\frac{5}{13} + \frac{8}{13} = \frac{13}{13} = 1$

Step 2: Add the whole numbers: $4 + 2 = 6$

So, $4 \frac{5}{13} + 2 \frac{8}{13} = 6 + 1 = 7$

Now, for the second mixed number: $1 \frac{12}{13} + 3 \frac{7}{13}$

Step 1: Add the fractions: $\frac{12}{13} + \frac{7}{13} = \frac{19}{13}$

Step 2: Add the whole numbers: $1 + 3 = 4$

So, $1 \frac{12}{13} + 3 \frac{7}{13} = 4 + \frac{19}{13}$

Now, subtract the results from Step 3:

$(4 \frac{5}{13} + 2 \frac{8/13}) - (1 \frac{12}{13} + 3 \frac{7}{13}) = (7) - (4 + \frac{19}{13})$

Now, subtract the fractions:

$(7) - (4 + \frac{19}{13}) = 7 - 4 - \frac{19}{13} = 3 - \frac{19}{13}$

To subtract fractions, you need a common denominator. In this case, the common denominator is 13.

$(3 \cdot 13/13) - \frac{19}{13} = \frac{39}{13} - \frac{19}{13}$

Now, subtract the fractions:

$\frac{39}{13} - \frac{19}{13} = \frac{39 - 19}{13} = \frac{20}{13}$

So, $(4 \frac{5}{13} + 2 \frac{8}{13}) - (1 \frac{12}{13} + 3 \frac{7}{13}) = \frac{20}{13}$

Therefore, the result of the expression is $\frac{20}{13}$, or you can also express it as a mixed number: $1 \frac{7}{13}$.