Question

1) 9(х-1)=х+15= 2)12-4(х-3)=39-9х=

Answer 1

1) 9х-9=х+15
    9х-х=15+9
    8х=24
      х=24:8
      х=3
2) 12-4х+12=39-9х
    -4х+9х=39-24
       5х=15
         х=15:5
         х=3.

Answer 2

It seems there might be some confusion in the equations you've provided. Equations typically have only one equals sign, so it's important to separate the equations properly. Let's work on solving them one by one:

1. $9(x - 1) = x + 15$:

First, distribute the 9 on the left side: $9x - 9 = x + 15$

Now, isolate the variable terms on one side and the constant terms on the other side: $9x - x = 15 + 9$ $8x = 24$

Divide both sides by 8: $x = 3$

So, the solution for this equation is $x = 3$.

2. $12 - 4(x - 3) = 39 - 9x$:

First, distribute the -4 on the left side: $12 - 4x + 12 = 39 - 9x$

Combine the constant terms on both sides: $24 - 4x = 39 - 9x$

Add $4x$ to both sides: $24 = 39 - 5x$

Subtract 39 from both sides: $-15 = -5x$

Divide both sides by -5: $3 = x$

So, the solution for this equation is $x = 3$.

It appears that both equations have the same solution $x = 3$, which means this is the value of $x$ that satisfies both equations. Please double-check the equations if they were intended to be different or if there was a typo in writing them.