Question

(y-4)×(y+4)-(y-3)^2=

Answer 1

Y2-16=(y-4)(y+4)
(y-3)2=y2-6y+9

Answer 2

Let's simplify the expression step by step:

1. Expand the first term: (y - 4) * (y + 4) = y^2 + 4y - 4y - 16 = y^2 - 16

2. Expand the second term: (y - 3)^2 = y^2 - 6y + 9

Now substitute these expansions back into the original expression:

(y^2 - 16) - (y^2 - 6y + 9)

Distribute the negative sign:

y^2 - 16 - y^2 + 6y - 9

Combine like terms:

6y - 16 - 9 = 6y - 25

So, the simplified expression is 6y - 25.