Question

3(х-1)-2(1+х)≤1, 3х-4≥0

Answer 1

Надеюсь, что так. Отметь как лучшее. Удачи!

Answer 2

To solve the inequalities, let's tackle them one by one.

1. 3(x - 1) - 2(1 + x) ≤ 1

Step 1: Distribute the terms inside the parentheses. 3x - 3 - 2 - 2x ≤ 1

Step 2: Combine like terms on the left-hand side. 3x - 2x - 5 ≤ 1

Step 3: Simplify the left-hand side. x - 5 ≤ 1

Step 4: Move the constant term to the right-hand side. x ≤ 1 + 5

Step 5: Final result. x ≤ 6

So the solution for the first inequality is x ≤ 6.

2. 3x - 4 ≥ 0

Step 1: Add 4 to both sides to isolate the variable term. 3x ≥ 4

Step 2: Divide both sides by 3 (since the coefficient of x is positive, we don't need to change the inequality direction). x ≥ 4/3

So the solution for the second inequality is x ≥ 4/3.

Now, to find the combined solution, we need to find the values of x that satisfy both inequalities.

The common region where both inequalities are true is where x is less than or equal to 6 and greater than or equal to 4/3.

So the combined solution is x ∈ [4/3, 6].