Question

Икс+735=1416, икс+852=15387, икс×48=15408

Answer 1

х+735=1416
х=1416-735
х=681

х+852=15387
х=15387-852
х=14535

х×48=15408
х=15408:48
х=321

Answer 2

To find the value of "x" in each equation, let's solve them one by one:

1. Equation 1: x + 735 = 1416 Subtract 735 from both sides to isolate "x": x = 1416 - 735 x = 681

So, x = 681 is the solution for the first equation.

2. Equation 2: x + 852 = 15387 Subtract 852 from both sides to isolate "x": x = 15387 - 852 x = 14535

So, x = 14535 is the solution for the second equation.

3. Equation 3: x × 48 = 15408 Divide both sides by 48 to isolate "x": x = 15408 ÷ 48 x = 321

So, x = 321 is the solution for the third equation.

To summarize:

1. x = 681
2. x = 14535
3. x = 321