Question

в 3 бочках 200 литров бензина в первый и во второй бочке 160 л а во второй и третий 134 Сколько литров бензина в каждой бочке

Answer 1

1)160+134-200=94(л)-во второй
2)160-94=66(л)-в первой
3)134-94=40(л)-в третей

Answer 2

1)200-134=66 в1 бочке
2)160-66=94 во 2 бочке
3)134-94=40 в 3 бочке

Answer 3

Let's assume there are three barrels: Barrel 1, Barrel 2, and Barrel 3. We need to find out how many liters of gasoline are in each barrel based on the information given.

Let's call the amount of gasoline in Barrel 1 as x liters, in Barrel 2 as y liters, and in Barrel 3 as z liters.

According to the given information:

1. In the first and second barrels, there are a total of 200 liters of gasoline: x + y = 200 ......... (Equation 1)

2. In the second and third barrels, there are a total of 134 liters of gasoline: y + z = 134 ......... (Equation 2)

3. In the first and third barrels, there are a total of 160 liters of gasoline: x + z = 160 ......... (Equation 3)

Now, we have a system of three equations (Equation 1, Equation 2, and Equation 3) with three unknowns (x, y, and z). We can solve these equations simultaneously to find the values of x, y, and z.

Subtract Equation 2 from Equation 1 to eliminate y: (x + y) - (y + z) = 200 - 134 x - z = 66 ......... (Equation 4)

Add Equation 1 and Equation 3 to eliminate z: (x + y) + (x + z) = 200 + 160 2x + y + z = 360 ......... (Equation 5)

Now, we have a simplified system of two equations:

Equation 4: x - z = 66 Equation 5: 2x + y + z = 360

Solve these equations to find the values of x, y, and z:

Add Equation 4 and Equation 5: x - z + 2x + y + z = 66 + 360 3x + y = 426

Now, let's isolate y in this equation: y = 426 - 3x ......... (Equation 6)

Now, use Equation 6 in either Equation 4 or Equation 5 to find the value of x or z. Let's use Equation 4:

x - z = 66 x - (426 - 3x) = 66 x - 426 + 3x = 66 4x = 492 x = 492 / 4 x = 123

Now that we have the value of x, we can find y using Equation 6: y = 426 - 3x y = 426 - 3 * 123 y = 426 - 369 y = 57

Finally, find z using Equation 2: z + y = 134 z = 134 - y z = 134 - 57 z = 77

So, the amount of gasoline in each barrel is: Barrel 1: 123 liters Barrel 2: 57 liters Barrel 3: 77 liters