Question

(2x-3)^2-(5x+6)^2=0 (^2 это квадрат)

Answer 1

Мгожно вопрос там между квадратом и 2 умножить стоит если да тогда ответ такой:
-6(х+3)умножить на (7х+3)

Answer 2

(2х-3)^2-(5х+6)^2=0
(2х-3)^2=(5х+6)^2

1. 2х-3=5х+6 => 3х+9=0 => х = -3
2. 2х-3=-5х-6 => 7х+3=0 => х = -3/7

Ответ: -3 или -3/7.

Answer 3

To solve the equation $(2x-3)^2 - (5x+6)^2 = 0$, we can first factor the left-hand side of the equation and then solve for $x$. The given equation is a difference of squares, which can be factored as follows:

$(2x-3)^2 - (5x+6)^2 = (2x-3 + 5x+6)(2x-3 - 5x-6) = (7x + 3)(-3x - 9) = 0$

Now, we have two factors on the left-hand side:

1. $7x + 3 = 0$
2. $-3x - 9 = 0$

Let's solve each equation for $x$:

1. $7x + 3 = 0$ Subtract 3 from both sides: $7x = -3$ Divide both sides by 7: $x = -\frac{3}{7}$

2. $-3x - 9 = 0$ Add 9 to both sides: $-3x = 9$ Divide both sides by -3: $x = -3$

So, the solutions for the equation are $x = -\frac{3}{7}$ and $x = -3$.