Question

При как значениях а система 2х+3у=5 ; 4х+6у=а

Answer 1

2x+3y=5
4x+6y=a 
Из первого уравнения выражаем Х , то есть:
x= $\frac{5+3y}{2}$
И подставляем вместо Х во втором уравнении: 
4* $\frac{5-3y}{2}$+6y=a
Упростим и приведем к общему знаменателю:
$\frac{4*5-3y*4}{2}+ \frac{6y*2}{2} = a$
$\frac{20-12y+12y }{2}$=a
20/2=a
a=10

Answer 2

А =10
Ведь 2 уравнение можно сократить на 2 и получится одно и тоже .
5×2 равно10

Answer 3

To find the values of x and y for the system of equations, we need to solve the two equations simultaneously. The system of equations is:

1. 2x + 3y = 5
2. 4x + 6y = a

We can use the method of substitution or elimination to solve this system. Let's use the substitution method:

Step 1: Solve one of the equations for one variable in terms of the other variable. Let's solve equation (1) for x: 2x = 5 - 3y x = (5 - 3y)/2

Step 2: Substitute the value of x from step 1 into the second equation (equation 2): 4((5 - 3y)/2) + 6y = a Now, simplify the equation:

2(5 - 3y) + 6y = a 10 - 6y + 6y = a 10 = a

So, when a = 10, the system of equations has infinitely many solutions, as the two equations are the same line. Any x and y that satisfy the first equation will automatically satisfy the second equation as well.

If a is any value other than 10, the system of equations will have no solution, as the two equations represent parallel lines that will never intersect.

In summary:

• When a = 10, the system has infinitely many solutions (all points on the line).
• For any other value of a, the system has no solution (no intersection point).