Question

Решить неравенства а) 6^x>1296

Answer 1

Вроде вот так вот, не за что

Answer 2

To solve the inequality 6^x > 1296, we can use logarithms. The base of the logarithm doesn't matter as long as it's consistent. Let's use the natural logarithm (base e) here:

1. Take the natural logarithm of both sides: ln(6^x) > ln(1296)

2. Apply the property of logarithms that states ln(a^b) = b * ln(a): x * ln(6) > ln(1296)

3. Now, isolate x by dividing both sides by ln(6): x > ln(1296) / ln(6)

4. Calculate the values on the right-hand side: x > 7.37657623037...

However, we must remember that x cannot be equal to 7.37657623037 since that would result in 6^x being equal to 1296. So the final solution for the inequality is:

x > 7.37657623037