Question

I2x-7I+9:(1,5)=4 "I"- ЭТО МОДУЛЬ А НЕ 1

Answer 1

|2x-7| возьмем за t
t+9\1.5=4
t=4-6
t=-2
|2x-7|=-2
Ну, либо тут скобки не расставлены, либо решений нет, модуль не может быть равен отрицательному числу

Answer 2

I understand that you are trying to evaluate the expression "I2x-7I+9" at the point (1, 5) and want to clarify that "I" represents the absolute value (modulus) and not the number 1.

To evaluate the expression at the given point, we need to substitute the value of "x" into the expression and perform the necessary calculations. Let's do that step by step:

1. Replace "x" with 1 in the expression: I2(1) - 7I + 9

2. Calculate 2(1) = 2 and |7| = 7 (since "I" represents the absolute value): 2 - 7 + 9

3. Perform the remaining arithmetic: -5 + 9

4. The final result is: 4

Therefore, when "x" is 1, the expression "I2x-7I+9" evaluates to 4.