
3+7+11+15+19+...Sn=210n=?


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Ответ: 10



The given series is an arithmetic sequence with a common difference of 4 between consecutive terms. The general formula for the nth term of an arithmetic sequence is given by:
a_n = a_1 + (n - 1) * d
Where: a_n = nth term a_1 = first term d = common difference n = term number
In this case: a_1 = 3 (the first term) d = 4 (the common difference)
Now, we need to find the sum of the first n terms of the series, which is given by the formula for the sum of an arithmetic sequence:
S_n = (n/2) * (a_1 + a_n)
Substitute the values of a_1 and a_n:
S_n = (n/2) * (3 + (3 + (n - 1) * 4)) S_n = (n/2) * (3 + 3 + 4n - 4) S_n = (n/2) * (6 + 4n)
Now, we want to find the value of Sn when S_n = 210n:
210n = (n/2) * (6 + 4n)
To solve for n, let's first simplify the equation:
210n = 3n + 2n^2
Now, let's put the equation in the standard quadratic form:
2n^2 + 3n - 210n = 0
Next, factor out common terms:
n(2n + 3 - 210) = 0
Now, set each factor to zero and solve for n:
- n = 0 (Ignore this solution since it doesn't make sense in this context.)
- 2n + 3 - 210 = 0 2n = 210 - 3 2n = 207 n = 207 / 2 n = 103.5
Since we are dealing with the number of terms, n cannot be a decimal; it must be a positive whole number. So, we can't use n = 103.5.
However, we can check if the sum of the first 103 terms is equal to 210 times the number of terms:
S_103 = (103/2) * (6 + 4 * 103) S_103 = 53 * 418 S_103 = 22154
Now, let's check if 22154 = 210 * 103:
210 * 103 = 21630
Since 22154 is less than 21630, we can conclude that n = 103 is the correct number of terms.
So, the value of 210n is 210 * 103 = 21630.


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