Question

(x-5) + 2 = 0 ( 4) 2x+8y=0 1/4x-8+2x=0 РЕШИТЕ УРАВНЕНИЯ

Answer 1

(x-5) + 2 = 0
х-5=-2
х=3
_______
2x+8y=0 
х=-4у
у∈R
_________
1/4x-8+2x=0 
2.25х=8
х=3 5/9

Answer 2

To solve the equations, we'll find the values of variables (x and y) that satisfy each equation.

1. Equation 1: (x - 5) + 2 = 0 Let's solve for x: x - 5 + 2 = 0 x - 3 = 0 x = 3

2. Equation 2: 2x + 8y = 0 Since there are two variables (x and y), we need another equation to solve for both x and y. If there's no second equation, we can't uniquely determine the values of x and y.

3. Equation 3: (1/4)x - 8 + 2x = 0 First, let's combine like terms: (1/4)x + 2x - 8 = 0

To solve for x, let's get rid of the fractions: Multiply the entire equation by 4 to eliminate the fraction: 4 * [(1/4)x] + 4 * (2x) - 4 * 8 = 4 * 0 x + 8x - 32 = 0

Combine the x terms: 9x - 32 = 0

Add 32 to both sides of the equation: 9x = 32

Now, divide both sides by 9 to solve for x: x = 32 / 9

So the solutions are:

1. x = 3
2. x = 32 / 9 (or approximately 3.56)

Please note that for Equation 2, without another equation involving x and y, we can't find unique values for x and y simultaneously. If you have another equation related to x and y, please provide it, and I can help you solve the system of equations.