Question

72-a=17*4 c+418=2005-1340 реши уравнения

Answer 1

72-a=17*4
72-а=68
а=72-68
а=4

c+418=2005-1340
с=665-418
с=247

Answer 2

72-а=17*4

72-а=68

а=72-68

а=4

с+418=2005-1340

с+418=665

с=665-418

с=247

Answer 3

To solve the equations, we'll isolate the variables on one side of the equation. Let's start with each equation one by one:

1. 72 - a = 17 * 4

Step 1: Simplify the right side of the equation. 72 - a = 68

Step 2: Isolate the variable 'a' by bringing 'a' to one side of the equation. Subtract 72 from both sides: 72 - a - 72 = 68 - 72

This simplifies to: -a = -4

Step 3: Solve for 'a' by multiplying both sides by -1 to get rid of the negative sign in front of 'a'. -a * (-1) = -4 * (-1)

This gives us: a = 4

So, the value of 'a' is 4.

2. c + 418 = 2005 - 1340

Step 1: Simplify the right side of the equation. c + 418 = 665

Step 2: Isolate the variable 'c' by bringing 'c' to one side of the equation. Subtract 418 from both sides: c + 418 - 418 = 665 - 418

This simplifies to: c = 247

So, the value of 'c' is 247.

Therefore, the solutions to the equations are: a = 4 c = 247