Question

2x(x-7)=3x-21 ..............

Answer 1

Надеюсь понятно)))))

Answer 2

To solve the equation 2x(x-7) = 3x-21, follow these steps:

Step 1: Distribute the term on the left side of the equation:

2x(x-7) = 2x * x - 2x * 7 = 2x^2 - 14x

So, the equation becomes: 2x^2 - 14x = 3x - 21

Step 2: Move all the terms to one side of the equation to set it equal to zero:

2x^2 - 14x - 3x + 21 = 0

Step 3: Combine like terms:

2x^2 - 17x + 21 = 0

Step 4: Now, we need to solve the quadratic equation. However, this equation cannot be factored easily, so we'll use the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

For our equation, a = 2, b = -17, and c = 21. Plug these values into the formula:

x = [ -(-17) ± √((-17)^2 - 4 * 2 * 21) ] / (2 * 2) x = [ 17 ± √(289 - 168) ] / 4 x = [ 17 ± √121 ] / 4 x = [ 17 ± 11 ] / 4

Now, we have two possible solutions:

1. x = (17 + 11) / 4 x = 28 / 4 x = 7

2. x = (17 - 11) / 4 x = 6 / 4 x = 3/2

So, the two solutions to the equation are x = 7 and x = 3/2.