Question

8 целых 3/7- 4 целых 2/5 =; 6 целых 11/15 - 2 целых 7/10 = ; 16 целых 17/18 - 2 целых 11/12 =; 18 целых 13/48 - 5 целых 3/64 =

Answer 1

1) 8$\frac{3}{7}$ - 4$\frac{2}{5}$ = $\frac{24}{7} - \frac{8}{5}$ = $\frac{120}{35} - \frac{56}{35}$ = $\frac{120-56}{35}$ = $\frac{64}{35}$ = 1 $\frac{29}{35}$

2) $6\frac{11}{15} - 2 \frac{7}{10}$ = 2$\frac{11}{5} - 2\frac{7}{10} = 2\frac{11}{5} - \frac{7}{5}$ = $\frac{22}{5} - \frac{7}{5}$ = $\frac{22-7}{5}$ = $\frac{15}{5} = 33) 16 [tex]\frac{17}{18} - 2 \frac{11}{12} = 8 \frac{17}{9} - 2 \frac{11}{12} = 8 \frac{17}{9} - \frac{11}{6}$ = $\frac{136}{9} - \frac{11}{6} = \frac{272}{18} - \frac{33}{18} = \frac{272-33}{18} = \frac{239}{18} = 13 \frac{5}{18}$

4) $18 \frac{13}{48} - 5 \frac{3}{64} = [tex]3 \frac{13}{8} - 5 \frac{3}{64} =3\frac{13}{8} - \frac{15}{64}$ = $\frac{39}{8} - \frac{15}{64} = \frac{312}{64} - \frac{15}{64} = \frac{312-15}{64} = \frac{297}{64}$ = $4 \frac{41}{64}$

Не забудьте про обозначение сокращений!

Answer 2

8 3/7-4 2/5=4 3/7-2/5=4 15-14/35=4 1/35

6 11/15-2 7/10=4 11/15-7/10=4 22-21/30=4 1/30

16 17/18-2 11/12=14 17/18-11/12=14 34-33/36=14 1/36

18 13/48-5 3/64=13 13/48-3/64=13 52/192-9/192=13 43/192

Answer 3

To solve these subtraction problems involving mixed numbers, you can follow these steps:

Step 1: Convert the mixed numbers into improper fractions. Step 2: Find a common denominator. Step 3: Subtract the fractions. Step 4: Simplify the result back to a mixed number, if necessary.

Let's solve each problem:

1. $8\frac{3}{7} - 4\frac{2}{5}$:

Step 1: Convert to improper fractions: $8\frac{3}{7} = \frac{8 \times 7 + 3}{7} = \frac{59}{7}$ $4\frac{2}{5} = \frac{4 \times 5 + 2}{5} = \frac{22}{5}$

Step 2: Find a common denominator (the least common multiple of 5 and 7 is 35).

Step 3: Subtract the fractions: $\frac{59}{7} - \frac{22}{5} = \frac{5 \times 59}{5 \times 7} - \frac{7 \times 22}{5 \times 7} = \frac{295}{35} - \frac{154}{35} = \frac{141}{35}$

Step 4: Simplify the result back to a mixed number: $\frac{141}{35} = 4\frac{1}{35}$

So, $8\frac{3}{7} - 4\frac{2}{5} = 4\frac{1}{35}$.

2. $6\frac{11}{15} - 2\frac{7}{10}$:

Step 1: Convert to improper fractions: $6\frac{11}{15} = \frac{6 \times 15 + 11}{15} = \frac{101}{15}$ $2\frac{7}{10} = \frac{2 \times 10 + 7}{10} = \frac{27}{10}$

Step 2: Find a common denominator (the least common multiple of 10 and 15 is 30).

Step 3: Subtract the fractions: $\frac{101}{15} - \frac{27}{10} = \frac{10 \times 101}{10 \times 15} - \frac{15 \times 27}{10 \times 15} = \frac{1010}{30} - \frac{405}{30} = \frac{605}{30}$

Step 4: Simplify the result back to a mixed number: $\frac{605}{30} = 20\frac{5}{30} = 20\frac{1}{6}$

So, $6\frac{11}{15} - 2\frac{7}{10} = 20\frac{1}{6}$.

3. $16\frac{17}{18} - 2\frac{11}{12}$:

Step 1: Convert to improper fractions: $16\frac{17}{18} = \frac{16 \times 18 + 17}{18} = \frac{305}{18}$ $2\frac{11}{12} = \frac{2 \times 12 + 11}{12} = \frac{35}{12}$