Question

Х÷112+15421=15423 1436÷у-268=91 Z×95-380=1235 (2437+a)÷3=57 2586÷(301+b)=6 (417-c)×48=1776

Answer 1

Х:112+15421=15423        1436;у-268=91      zх95-380=1235  

х:112=15423-15421          1436:у=91+268     zх95=1235+380  

х:112=2                             1436:у=359           zх95=1615

х=2х112                             у=1436:359           z=1615:95

х=224                                у=4                        z=17

2586:(301+b)=6               (2437-а):3=57         (417-с)х48=1776

301+b=2586^6                 2437-а=57х3          417-с=1776:48

301+b=431                         2437-а=171              417-с=37

b=431-301                           а=2437-171              с=417-37

b=130                                   а=2266                   с=380

Answer 2

Правильно !!!!!!!!!!!!!!!!!!!!!!!!

Answer 3

It looks like you have provided a series of equations with variables represented by different symbols (÷, +, -, ×) and asked for the values of the variables. Let's solve each equation step by step:

1. Х ÷ 112 + 15421 = 15423

To find the value of Х, we can first move the constant term to the other side:

Х ÷ 112 = 15423 - 15421 Х ÷ 112 = 2

Now, to isolate Х, we'll multiply both sides by 112:

Х = 2 × 112 Х = 224

So, the value of Х is 224.

2. 1436 ÷ у - 268 = 91

To find the value of у, we'll first move the constant term to the other side:

1436 ÷ у = 91 + 268 1436 ÷ у = 359

Now, to isolate у, we'll divide both sides by 1436:

у = 1436 ÷ 359 у = 4

So, the value of у is 4.

3. Z × 95 - 380 = 1235

To find the value of Z, we'll first move the constant term to the other side:

Z × 95 = 1235 + 380 Z × 95 = 1615

Now, to isolate Z, we'll divide both sides by 95:

Z = 1615 ÷ 95 Z = 17

So, the value of Z is 17.

4. (2437 + a) ÷ 3 = 57

To find the value of a, we'll first move the constant term to the other side:

(2437 + a) ÷ 3 = 57 2437 + a = 57 × 3 2437 + a = 171

Now, to isolate a, we'll subtract 2437 from both sides:

a = 171 - 2437 a = -2266

So, the value of a is -2266.

5. 2586 ÷ (301 + b) = 6

To find the value of b, we'll first move the constant term to the other side:

2586 ÷ (301 + b) = 6

Now, we can multiply both sides by (301 + b) to isolate the fraction:

2586 = 6 × (301 + b) 2586 = 1806 + 6b

Next, we'll isolate 6b by subtracting 1806 from both sides:

6b = 2586 - 1806 6b = 780

Finally, to find the value of b, we'll divide both sides by 6:

b = 780 ÷ 6 b = 130

So, the value of b is 130.

6. (417 - c) × 48 = 1776

To find the value of c, we'll first move the constant term to the other side:

(417 - c) × 48 = 1776

Next, divide both sides by 48 to isolate the expression (417 - c):

417 - c = 1776 ÷ 48 417 - c = 37

Now, isolate c by subtracting 417 from both sides:

c = 417 - 37 c = 380

So, the value of c is 380.

Here are the solutions to the equations:

Х = 224 у = 4 Z = 17 a = -2266 b = 130 c = 380