Question

{8y-7x=-5,6 35x+2y=7 Смотреть ответ Hudoyberdi Hudoyberdi

Answer 1

It seems like you've provided two equations:

1. $8y - 7x = -5$
2. $35x + 2y = 7$

To find the solution to this system of equations, we can use either the substitution method or the elimination method. I'll demonstrate the elimination method here:

Step 1: Multiply the first equation by 2 and the second equation by 7 to make the coefficients of y the same:

$2(8y - 7x) = 2(-5) \Rightarrow 16y - 14x = -10$
$7(35x + 2y) = 7(7) \Rightarrow 245x + 14y = 49$

Step 2: Now, let's eliminate one of the variables. We can eliminate y by adding the two equations together:

$(16y - 14x) + (14y + 245x) = -10 + 49$
$30y + 231x = 39$

Step 3: Now, we can solve for y:

$30y = -231x + 39$
$y = \frac{-231x + 39}{30}$

Step 4: Substitute the value of y into one of the original equations. Let's use the first equation:

$8\left(\frac{-231x + 39}{30}\right) - 7x = -5$

Step 5: Solve for x:

Multiply everything by 30 to eliminate the fraction:

$8(-231x + 39) - 210x = -150$
$-1848x + 312 - 210x = -150$
$-2058x + 312 = -150$
$-2058x = -150 - 312$
$-2058x = -462$
$x = \frac{-462}{-2058}$
$x \approx 0.2244$

Step 6: Now that we have the value of x, we can find y by substituting the value of x into one of the original equations. Let's use the first equation:

$8y - 7(0.2244) = -5$
$8y - 1.571$
$8y = -5 + 1.571$
$8y = -3.429$
$y = \frac{-3.429}{8}$
$y \approx -0.4286$

So, the solution to the system of equations is approximately $x \approx 0.2244$ and $y \approx -0.4286$.