Question

-5x²+2x+2x-8x+3x²+9x+12=0 Решите уравнение!

Answer 1

-2x²+5x+12 = 0.
D = b²-4ac = 25-4*(-2)*12 = 121. √D = 11.
x(1) = (-5+11)/(-4) = -(6/4) = -1,5.
x(2) = (-5-11)/(-4) = 4.
ответ : х(1) = -1,5 ; х(2) = 4.

Answer 2

-2х²+5х+12=0

д=25-4*(-2)*12=25+96=121

х1х2=-5±11 дробь 2*(-2)

х1=-5-11 дробь -4=-16\-4=4

х2=-5+11 дробь  -4=6\-4=-1.5

Answer 3

To solve the given equation, we first need to combine like terms:

-5x² + 2x + 2x - 8x + 3x² + 9x + 12 = 0

Combine the x² terms and the x terms:

(-5x² + 3x²) + (2x + 2x - 8x + 9x) + 12 = 0

-2x² + 5x + 12 = 0

Now, we have a quadratic equation in the form of ax² + bx + c = 0, where a = -2, b = 5, and c = 12. To solve this equation, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

Substitute the values of a, b, and c:

x = (-(5) ± √(5² - 4(-2)(12))) / 2(-2)

x = (-5 ± √(25 + 96)) / -4

x = (-5 ± √121) / -4

x = (-5 ± 11) / -4

Now, find the two possible values of x:

1. x = (-5 + 11) / -4 x = 6 / -4 x = -3/2

2. x = (-5 - 11) / -4 x = -16 / -4 x = 4

So, the solutions to the equation are x = -3/2 and x = 4.