Question

Известно, что функция g(x) –четная. а функция t(x)- нечетная. Рассчитать значение функции y = g(-x) + t(-x) в точке m, если известно, что g(m) = 22 un t(m) = 16.

Answer 1

для четной функции: f(-x)=f(x)

для нечетной: f(-x)=-f(x)

y=g(-x)+t(-x)=g(x)-t(x)

y(m)=g(m)-t(m)=22-16=6

Ответ: 6

Answer 2

Since g(x) is an even function, it follows the property g(x) = g(-x). And since t(x) is an odd function, it follows the property t(x) = -t(-x). Now, let's calculate the value of y = g(-x) + t(-x) at point m.

Given that g(m) = 22 and t(m) = 16, we can use the properties of even and odd functions to calculate y.

1. For the even function g(x): g(m) = g(-m) So, g(-m) = 22.

2. For the odd function t(x): t(m) = -t(-m) Now, rearranging the equation, we get: t(-m) = -t(m) t(-m) = -16

Now, we can calculate y = g(-m) + t(-m): y = 22 + (-16) y = 22 - 16 y = 6

Therefore, the value of the function y = g(-x) + t(-x) at point m is 6.