Question

1)16:(9-х)+8≈10 2)(4·х-130):7≈50

Answer 1

1)16:(9-х)+8≈10

16/9-х=2

2(9-х)=16

18-2х=16

-2х=-2

х=1

2)(4·х-130):7≈50

4х-130=350

4х=350+130

4х=480

х=120

Answer 2

To solve these equations, we'll first simplify them and then find the value of 'x' that satisfies the equations. Let's solve each equation step-by-step:

1. 16:(9-x) + 8 ≈ 10

Step 1: Remove the parentheses by distributing the division: 16/ (9-x) + 8 ≈ 10

Step 2: Subtract 8 from both sides to isolate the fraction on the left side: 16/(9-x) ≈ 2

Step 3: Now, we'll cross-multiply: 16 ≈ 2(9-x)

Step 4: Divide both sides by 2: 8 ≈ 9 - x

Step 5: Finally, isolate 'x' by subtracting 9 from both sides: x ≈ 9 - 8 x ≈ 1

So, the value of 'x' that satisfies the equation is x ≈ 1.

2. (4x - 130) / 7 ≈ 50

Step 1: Multiply both sides by 7 to eliminate the division: 4x - 130 ≈ 7 * 50

Step 2: Simplify the right side: 4x - 130 ≈ 350

Step 3: Add 130 to both sides to isolate '4x' on the left side: 4x ≈ 350 + 130 4x ≈ 480

Step 4: Finally, divide both sides by 4 to find 'x': x ≈ 480 / 4 x ≈ 120

So, the value of 'x' that satisfies the equation is x ≈ 120.

To summarize:

1. x ≈ 1
2. x ≈ 120