Question

Log3 *27+log4*16+log2*32 вычислите

Answer 1

Ответ:

Пошаговое объяснение:log2 16+ log3 27 - log4 16=4+3-2=5

Answer 2

To solve this expression, we need to use the properties of logarithms. Remember that the logarithm of a number with a specific base represents the exponent to which the base must be raised to obtain that number.

Let's calculate the expression step by step:

1. log3(27) = 3, because 3^3 = 27
2. log4(16) = 2, because 4^2 = 16
3. log2(32) = 5, because 2^5 = 32

Now, let's substitute these values back into the original expression:

log3(27) + log4(16) + log2(32) = 3 + 2 + 5 = 10

So, the final result is 10.