To solve the equation 53(21x+31)=41x+247, follow these steps:
Step 1: Clear the fractions
To eliminate the fractions, we can multiply both sides of the equation by the least common multiple (LCM) of the denominators. The LCM of 2, 3, and 24 is 24.
So, multiply both sides by 24:
24×[53(21x+31)]=24×[41x+247]
Step 2: Simplify
On the left-hand side:
24×[53(21x+31)]=24×[53×21x+53×31]
=24×[103x+51]=24×103x+24×51
=1072x+524=536x+524
On the right-hand side:
24×[41x+247]=24×41x+24×247
=6x+7
Step 3: Solve for x
Now the equation becomes:
536x+524=6x+7
Let's isolate the x term on one side and the constant term on the other:
536x−6x=7−524
536x−530x=535
56x=535
Now, multiply both sides by the reciprocal of 56 to solve for x:
x=56535
x=535×65