Question

Функция задана формулой f(x) =x²-16 A) найдите f(-2),f(0) B) найдите значения x, при которых f(x) =-12;f(x)=0

Answer 1

Ответ:

Пошаговое объяснение:

A) в функцию f(x)=x^2-16 подставляем

x=-2 и 0 чтобы найти f(-2) и f(0)

f(-2)=(-2)^2-16=4-16=-12

f(0)=-16

B) мы уже нашли что при x=-2 наша функция равна f(x)=-12 а чтобы найти x в f(x)=0

Нужно функцию приравнять к нулю

x^2-16=0 от суда x=4 и x=-4

Answer 2

To find the values of the function f(x) = x² - 16, we can simply substitute the given values of x into the function and calculate the corresponding outputs.

A) Find f(-2) and f(0):

a) f(-2): f(-2) = (-2)² - 16 f(-2) = 4 - 16 f(-2) = -12

b) f(0): f(0) = (0)² - 16 f(0) = 0 - 16 f(0) = -16

B) Find the values of x for which f(x) equals -12 and 0:

a) f(x) = -12: We need to find the values of x for which f(x) is equal to -12. So, we set up the equation:

x² - 16 = -12

Adding 12 to both sides:

x² = -12 + 16 x² = 4

Taking the square root of both sides:

x = ±√4 x = ±2

So, the values of x for which f(x) = -12 are x = 2 and x = -2.

b) f(x) = 0: Similarly, we need to find the values of x for which f(x) is equal to 0. So, we set up the equation:

x² - 16 = 0

Adding 16 to both sides:

x² = 16

Taking the square root of both sides:

x = ±√16 x = ±4

So, the values of x for which f(x) = 0 are x = 4 and x = -4.