Question

Y=4x^2+3x-1 пересечение с х

Answer 1

Пересечение будет при х=-1, т.к. Точка пересечения будет иметь координаты 0 по оси Ох(абсцисс).

Answer 2

To find the intersection points with the x-axis, we need to set the value of y to 0 and solve for the corresponding values of x. In other words, we need to find the values of x when the equation Y = 4x^2 + 3x - 1 equals zero.

So, we set Y = 0 and solve for x:

0 = 4x^2 + 3x - 1

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 4, b = 3, and c = -1.

x = (-(3) ± √(3^2 - 4 * 4 * -1)) / 2 * 4 x = (-3 ± √(9 + 16)) / 8 x = (-3 ± √25) / 8 x = (-3 ± 5) / 8

Now, we have two possible values for x:

1. x = (-3 + 5) / 8 x = 2 / 8 x = 1/4

2. x = (-3 - 5) / 8 x = -8 / 8 x = -1

So, the equation Y = 4x^2 + 3x - 1 intersects the x-axis at two points: (1/4, 0) and (-1, 0).