Question

1/4(0, 4+х) =3/8х+1, 1

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve the equation, we need to find the value of x that satisfies the equation:

1/4(0, 4 + x) = 3/8x + 1

However, there seems to be a typo in the equation you provided. The term "(0, 4 + x)" doesn't make sense in this context. I assume you meant "(0, 4 + x)" to be "(0, 4 + x)" or "(0, 4) + x", but it's not entirely clear.

I will provide two interpretations of the equation, and you can let me know which one is correct:

1. If the equation is: 1/4(0, 4) + x = 3/8x + 1

In this case, the equation becomes:

1/4 * 4 + x = 3/8x + 1 1 + x = 3/8x + 1

Now, let's solve for x:

1 + x - 1 = 3/8x x = (3/8x - 1) x - 3/8x = -1 (8x^2 - 3x) / 8x = -1 8x^2 - 3x = -8x 8x^2 + 5x = 0

Now, we can solve this quadratic equation for x. Factoring the equation, we get:

x(8x + 5) = 0

Setting each factor to zero:

1. x = 0
2. 8x + 5 = 0 8x = -5 x = -5/8

So, the solutions for x are x = 0 and x = -5/8.

2. If the equation is: 1/4(0, 4 + x) = 3/(8x + 1)

In this case, the equation becomes:

1/4 * (4 + x) = 3/(8x + 1)

Let's solve for x:

(4 + x)/4 = 3/(8x + 1)

Cross-multiply:

(4 + x)(8x + 1) = 3 * 4

Expand and simplify:

32x + 4 + 8x^2 + x = 12

Rearrange as a quadratic equation:

8x^2 + 33x + 4 - 12 = 0

8x^2 + 33x - 8 = 0

Now, we can solve this quadratic equation for x. Using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 8, b = 33, and c = -8.

x = (-33 ± √(33^2 - 4 * 8 * -8)) / 2 * 8 x = (-33 ± √(1089 + 256)) / 16 x = (-33 ± √1345) / 16

The solutions for x are approximately:

x ≈ -2.353 and x ≈ 0.186

Please clarify the equation if neither of these interpretations is correct.