Question

10(n+m)-4(2m+7n); 11(5c+d)+3(d+c)​

Answer 1

1) 10n+10m-8m-28n=-18n+2m
2)55c+11d+3d+3c=58c+14d

Answer 2

Ответ:

10n+10m-8m-28n=2m-18n

55c+11d+3d+3c=58c+14d

Answer 3

To simplify the expressions, let's perform the operations step by step.

1. Simplify 10(n+m) - 4(2m+7n):

Expand the expressions inside the parentheses: 10(n+m) - 4(2m+7n) = 10n + 10m - 8m - 28n

Combine like terms: 10n - 28n = -18n 10m - 8m = 2m

Final expression: 10(n+m) - 4(2m+7n) = 2m - 18n

2. Simplify 11(5c+d) + 3(d+c):

Expand the expressions inside the parentheses: 11(5c+d) + 3(d+c) = 55c + 11d + 3d + 3c

Combine like terms: 55c + 3c = 58c 11d + 3d = 14d

Final expression: 11(5c+d) + 3(d+c) = 58c + 14d

So, the simplified expressions are:

1. 10(n+m) - 4(2m+7n) = 2m - 18n
2. 11(5c+d) + 3(d+c) = 58c + 14d