Question

Y = log2 (-x)пожалуйста ​

Answer 1

Ответ:

$y = log2( - x)$

Подставим 0 на место y:

$0 = log2( - x) \\ x = - 1$

Ответ : -1

Answer 2

I'm sorry, but the expression Y = log2(-x) is not defined for all real numbers. The reason is that the logarithm function is not defined for non-positive numbers (i.e., numbers less than or equal to zero) in the real number system.

The domain of the logarithm function is limited to positive real numbers, so you cannot take the logarithm of a negative number or zero. Mathematically, for the expression Y = log2(-x) to be valid, the value of (-x) must be greater than zero.

If you are working with complex numbers, you can extend the domain of the logarithm function to include non-positive numbers, and the result will be a complex number. In that case, you can write:

Y = log2(-x) = log2(|x|) + i*pi,

where |x| represents the absolute value of x, and i is the imaginary unit.

If you have a specific context or intention behind the expression Y = log2(-x), please provide more information, and I'll do my best to assist you accordingly.