Question

1)3|×|+|×|=202)5|×|-3|×|=333)19|×|-17=16|×|4)42-63|×|=65|×|​

Answer 1

Ответ:

1)4х=20

х=5

2)2х=33

х=16,5

3)19х-16х=17

3х=17

х=5⅔

4)-128х=-42

х=0,328125

Answer 2

To solve these equations, let's go through them one by one:

1. 3|×| + |×| = 20

Since both terms on the left side contain |×| (absolute value), we can combine them into a single term:

4|×| = 20

Dividing both sides by 4, we get:

|×| = 5

So the solution is × = 5 or × = -5.

2. 5|×| - 3|×| = 33

Similarly, we combine the absolute value terms:

2|×| = 33

Dividing both sides by 2:

|×| = 16.5

Since absolute value cannot be negative, there is no solution to this equation.

3. 19|×| - 17 = 16|×|

Again, combining the absolute value terms:

3|×| = 17

Dividing both sides by 3:

|×| = 5.67

Since absolute value cannot be negative, the solution is × = 5.67 or × = -5.67.

4. 42 - 63|×| = 65|×|

Moving the absolute value terms to one side:

-63|×| - 65|×| = 42

Combining like terms:

-128|×| = 42

Dividing both sides by -128:

|×| = -0.328125

Since absolute value cannot be negative, there is no solution to this equation.

Therefore, the solutions to the given equations are:

1. × = 5 or × = -5
2. No solution
3. × = 5.67 or × = -5.67
4. No solution