Question

1) (а+3)×(в+7) 2)(f+4)×(z+8) 3)(12+k)×(4-m) 4)(t-3)×(p+1)

Answer 1

Ответ:

Пошаговое объяснение:

(a+3)(b+7)=7a+ab+3b+21

(f+4)(z+8)=8f+fz+4z+32

(12+k)(4-m)=4k-km-12m+48

(t-3)(p+1)=-3p+pt+t-3

Answer 2

1. To simplify the expression (a+3)×(b+7), you can use the distributive property of multiplication over addition.

First, distribute the (a+3) term to both terms inside the second parentheses: (a+3)×b + (a+3)×7

Now, simplify each term separately: (a×b + 3×b) + (7a + 3×7)

The simplified expression is: ab + 3b + 7a + 21

2. Similarly, for (f+4)×(z+8): Distribute the (f+4) term to both terms inside the second parentheses: (f+4)×z + (f+4)×8

Simplify each term separately: (f×z + 4×z) + (8f + 4×8)

The simplified expression is: fz + 4z + 8f + 32

3. For (12+k)×(4-m): Distribute the (12+k) term to both terms inside the second parentheses: (12+k)×4 + (12+k)×(-m)

Simplify each term separately: (12×4 + k×4) + (12×(-m) + k×(-m))

The simplified expression is: 48 + 4k - 12m - km

4. Lastly, for (t-3)×(p+1): Distribute the (t-3) term to both terms inside the second parentheses: (t-3)×p + (t-3)×1

Simplify each term separately: (t×p - 3×p) + (t×1 - 3×1)

The simplified expression is: tp - 3p + t - 3