Question

-3x^2+4x-7=-x+5x-(-1x+2x^2)

Answer 1

Ответ:

x^2+x+7=0

Пошаговое объяснение:

-3x^2+4x-7=-x+5x-(-x+2x^2)

-3x^2+4x-7=-x+5x+х-2х^2

-3х^2+4x-7+x-5x-x+2x^2=0

-x^2-x-7=0 /:(-1)

x^2+x+7=0

Answer 2

-3x²+4x-7=-x+5x-(-1x+2x²)

-3x²+4x-7+x-5x-1x+2x² = 0

-x²-x+7 = 0

Решим дискриминантом.

D = b²-4ac => 1-4*(-1)*7 = 1+28 = √29 > 0, 2 корня.

x = $\frac{-b+-\sqrt{D} }{2a}$

x₁ = $\frac{1+29}{-2} = -15$

x₂ = $\frac{1-29}{-2} = 14$

Ответ: -15;14.

Answer 3

Let's simplify the given equation step by step.

-3x^2 + 4x - 7 = -x + 5x - (-1x + 2x^2)

First, distribute the negative sign inside the parentheses:

-3x^2 + 4x - 7 = -x + 5x - (-x) + (-2x^2)

Next, combine like terms on both sides of the equation:

-3x^2 + 4x - 7 = -x + 5x + x - 2x^2

Rearrange the terms:

-3x^2 - 2x^2 + 4x + x + 5x + x - 7 = 0

Combine like terms:

-5x^2 + 11x - 7 = 0

So the simplified form of the given equation is -5x^2 + 11x - 7 = 0.