Question

3 1/6 +(-2 5/6)+1 7/12 решить удобым способом

Answer 1

$3\dfrac16+\bigg(-2\dfrac 56\bigg)+1\dfrac 7{12}=3\dfrac16^{(2}+1\dfrac 7{12}+\bigg(-2\dfrac 56\bigg)=\\\\\\=3\dfrac2{12}+1\dfrac 7{12}-2\dfrac 56^{(2}=4\dfrac 9{12}-2\dfrac {10}{12}=3\dfrac{21}{12}-2\dfrac {10}{12}=\\\\\\\boldsymbol{=1\dfrac {11}{12}}$

Answer 2

$\displaystyle \tt 3\frac{1}{6}+(-2\frac{5}{6})+1\frac{7}{12}=\frac{19}{6}-\frac{17}{6}+\frac{19}{12}=\frac{2}{6}+\frac{17}{12}=\frac{4}{12}+\frac{19}{12}=\frac{23}{12}=1\frac{11}{12}$

Answer 3

To solve the given expression:

3 1/6 + (-2 5/6) + 1 7/12, we can simplify it step by step.

First, let's convert the mixed numbers into improper fractions:

3 1/6 = (6 * 3 + 1) / 6 = 19/6 -2 5/6 = (6 * -2 + 5) / 6 = -17/6 1 7/12 = (12 * 1 + 7) / 12 = 19/12

Now we can rewrite the expression as the sum of fractions:

19/6 + (-17/6) + 19/12

To add fractions with different denominators, we need to find a common denominator. In this case, the least common multiple (LCM) of 6 and 12 is 12.

We can convert the fractions to have a common denominator of 12:

(19/6) * (2/2) = 38/12 (-17/6) * (2/2) = -34/12 19/12

Now we can add the fractions together:

38/12 + (-34/12) + 19/12

To add fractions with the same denominator, we simply add their numerators:

(38 - 34 + 19) / 12 = 23/12

Therefore, 3 1/6 + (-2 5/6) + 1 7/12 equals 23/12.