Question

(х+7)(х-1)=0 х(х+2,8)(3,5-х)=0

Answer 1

Пошаговое объяснение:

(х + 7)(х - 1) = 0

х + 7 = 0

х - 1 = 0

х1 = - 7. х2 = 1

х(х + 2,8)(3,5 - х) = 0

х(х + 14/5)(7/2 - х) = 0

х = 0

х + 14/5 = 0

7/2 - х = 0

х1 = - 14/5 х2 = 0 х3 = 7/2

Вот такой ответ! удачи)

Answer 2

To find the solutions for the given equations, we set each factor to zero and solve for the variable "х":

1. Equation 1: (х + 7)(х - 1) = 0

Setting each factor to zero: х + 7 = 0 => х = -7 х - 1 = 0 => х = 1

The solutions for Equation 1 are х = -7 and х = 1.

2. Equation 2: х(х + 2.8)(3.5 - х) = 0

Setting each factor to zero: х = 0 х + 2.8 = 0 => х = -2.8 3.5 - х = 0 => х = 3.5

The solutions for Equation 2 are х = 0, х = -2.8, and х = 3.5.

So, the solutions for the given equations are: Equation 1: х = -7 and х = 1. Equation 2: х = 0, х = -2.8, and х = 3.5.