Question

9х^2+12х+4=0 плизззз​

Answer 1

9х^2+12х+4=0

Д=144-144=0

х=-12+-0/2=-12/18

х=-6/9

х=-2/3

Answer 2

To solve the quadratic equation 9x^2 + 12x + 4 = 0, we can use the quadratic formula:

For an equation of the form ax^2 + bx + c = 0, the quadratic formula is:

x = (-b ± √(b^2 - 4ac)) / 2a

In our equation, a = 9, b = 12, and c = 4.

Let's plug these values into the formula:

x = (-(12) ± √(12^2 - 4 * 9 * 4)) / (2 * 9) x = (-12 ± √(144 - 144)) / 18 x = (-12 ± √0) / 18

Since the discriminant (b^2 - 4ac) is zero, we will have only one real root:

x = (-12 + 0) / 18 x = -12 / 18 x = -2/3

Therefore, the solution to the equation 9x^2 + 12x + 4 = 0 is x = -2/3.