Question

14×(400÷х-10)-12=72​

Answer 1

14*(400:х-10)=72+12
14*(400:х-10)=84
400:х-10=84:14
400:х-10=6
400:х=6+10
400:х=16
Х=400*16
Х=6.400

Answer 2

To solve the equation, we need to find the value of 'x' that satisfies the equation:

14 × (400 ÷ x - 10) - 12 = 72

Let's solve step by step:

Step 1: Simplify the expression inside the parentheses: 400 ÷ x - 10

Step 2: Perform the division: 400 ÷ x = 400x⁻¹

Step 3: Rewrite the expression with a positive exponent: 400x⁻¹ - 10

Step 4: Now, multiply by 14: 14 × (400x⁻¹ - 10)

Step 5: Distribute the multiplication: 14 × 400x⁻¹ - 14 × 10 = 5600x⁻¹ - 140

Step 6: Finally, add 12 to both sides to isolate the variable 'x': 5600x⁻¹ - 140 + 12 = 72 + 12

Step 7: Combine like terms: 5600x⁻¹ - 128 = 84

Step 8: Now, let's isolate the term with 'x': 5600x⁻¹ = 84 + 128

Step 9: Simplify the right-hand side: 5600x⁻¹ = 212

Step 10: Divide both sides by 5600 to solve for 'x': x⁻¹ = 212 / 5600

Step 11: Take the reciprocal of both sides to get the final value of 'x': x = 5600 / 212 x ≈ 26.42

So, the approximate value of 'x' that satisfies the equation is 26.42.