Question

(a³+2a⁴-3a³):(-a³)+(a-1)(a+1) при а=2​

Answer 1

Ответ:

(a³+2a⁴-3a³):(-a³)+(a-1)(a+1)= -2а³+2а⁴÷-а³+а²-1=-2×2³+2×2⁴÷-2³+2²-1=

16÷-5= -3,2

Пошаговое объяснение:

Answer 2

Ответ:

$\frac{ {a}^{3} + {a}^{4} - 3 {a}^{3} }{ { - a}^{3} } + {a}^{2} - 1 = - 1 - a + 3 + {a}^{2} - 1 = {a}^{2} - a + 1$

2*2-2+1=3

Answer 3

To evaluate the expression (a³ + 2a⁴ - 3a³) / (-a³) + (a - 1)(a + 1) when a = 2, we need to substitute the value of a into the expression and then simplify it step by step.

Step 1: Substitute a = 2 into the expression. (a³ + 2a⁴ - 3a³) / (-a³) + (a - 1)(a + 1) = (2³ + 2(2)⁴ - 3(2)³) / (-2³) + (2 - 1)(2 + 1)

Step 2: Calculate the values inside the parentheses and simplify the expressions. = (8 + 2(16) - 3(8)) / (-8) + (1)(3) = (8 + 32 - 24) / (-8) + 3 = 16 / (-8) + 3 = -2 + 3 = 1

So, when a = 2, the expression (a³ + 2a⁴ - 3a³) / (-a³) + (a - 1)(a + 1) equals 1.