Question

1) 7(x + 4) = −28 2) 35 = −5(2x − 1) 3) 9(−3x + 12) = 81 помогите решить пожайлуста!!!!

Answer 1

Ответ:

Пошаговое объясныение:

Answer 2

Ответ:

1) 7(х+4)=-28

7х+28=-28

7х=-28-28

7х=-56

х=-8

2)35=-5(2х-1)

7=-(2х-1)

7=-2х+1

2х=1-7

2х=-6

х=3

3)9(-3х+12)=81

-27х+108=81

-27х=81-108

-27х=-27

х=1

Answer 3

1. Let's solve the equation step by step:

7(x + 4) = -28

First, distribute 7 to the terms inside the parentheses:

7x + 28 = -28

Now, subtract 28 from both sides of the equation:

7x = -28 - 28

7x = -56

Finally, divide both sides of the equation by 7 to isolate x:

x = -56 / 7

x = -8

Therefore, the solution to the equation is x = -8.

2. Let's solve the equation step by step:

35 = -5(2x - 1)

First, distribute -5 to the terms inside the parentheses:

35 = -10x + 5

Now, subtract 5 from both sides of the equation:

35 - 5 = -10x

30 = -10x

Finally, divide both sides of the equation by -10 to isolate x:

x = 30 / -10

x = -3

Therefore, the solution to the equation is x = -3.

3. Let's solve the equation step by step:

9(-3x + 12) = 81

First, distribute 9 to the terms inside the parentheses:

-27x + 108 = 81

Now, subtract 108 from both sides of the equation:

-27x = 81 - 108

-27x = -27

Finally, divide both sides of the equation by -27 to isolate x:

x = -27 / -27

x = 1

Therefore, the solution to the equation is x = 1.

I hope this helps! Let me know if you have any further questions.