Question

72/80-(х-12/80)=15/80 116/125-(41)125-х)=94/1254/40+у+16/40=31/49+6/4060/90-(6/90+х)=29/90​

Answer 1

1)72/80-(x - 12/80) = 15/80

60/80 - x = 15/80

x = 60/80 - 15/80

x = 45/80

x = 9/16

2)116/125-(41)125-х)=94/125

41/125-x=116/125-94/125

41/125-x=22/125

x=41/125-22/125

x=19/125

3)4/40+у+16/40=31/49+6/40

1/2+y=31/49*3/20

1/2+y=93/980

y=93/980-1/2

y=-397/980

4)60/90-(6/90+х)=29/90​

6/90+x=60/90-29/90

6/90+x=31/90

x=31/90-6/90

x=25/90

Answer 2

Ответ:

1) 72/80 - (x - 12/80) = 15/80

72/80 - x + 12/80 = 15/80

84/80 - x = 15/80

-x = 15/80 - 84/80

x = 69/80

2) 116/125 - (41/125 - x) = 94/125

116/125 - 41/125 + x = 94/125

75/125 + x = 94/125

x = 94/125 - 75/125 = 19/125

3) 4/40 + y + 16/40 = 31/49 + 6/40

20/40 + y = 31/49 + 6/40

y = 31/49 + 6/40 - 20/40 = 31/49 - 14/40

4) 60/90 - 6/90 - x = 29/90

54/90 - x = 29/90

-x = -25/90 = 25/90 = 5/18

Answer 3

To solve the equations, let's start by simplifying each of them step by step:

1. $\frac{72}{80} - \left(\frac{x-12}{80}\right) = \frac{15}{80}$

Step 1: Combine fractions on the left side: $\frac{72 - (x - 12)}{80} = \frac{15}{80}$

Step 2: Simplify the numerator on the left side: $\frac{72 - x + 12}{80} = \frac{15}{80}$

Step 3: Combine like terms: $\frac{84 - x}{80} = \frac{15}{80}$

Step 4: Cross-multiply: $84 - x = 15$

Step 5: Solve for x: $x = 84 - 15 = 69$

So, the solution for this equation is $x = 69$.

2. $\frac{116}{125} - \left(\frac{41 \cdot 125 - x}{125}\right) = \frac{94}{125}$

Step 1: Combine fractions on the left side: $\frac{116 - (41 \cdot 125 - x)}{125} = \frac{94}{125}$

Step 2: Simplify the numerator on the left side: $\frac{116 - 5125 + x}{125} = \frac{94}{125}$

Step 3: Combine like terms: $\frac{-5019 + x}{125} = \frac{94}{125}$

Step 4: Cross-multiply: $-5019 + x = 94$

Step 5: Solve for x: $x = 94 + 5019 = 5113$

So, the solution for this equation is $x = 5113$.

3. $\frac{4}{40} + y + \frac{16}{40} = \frac{31}{49} + \frac{6}{40}$

Step 1: Combine fractions on both sides: $\frac{4 + 16}{40} + y = \frac{31 \cdot 40 + 6}{49 \cdot 40}$

Step 2: Simplify the fractions: $\frac{20}{40} + y = \frac{1240 + 6}{1960}$

Step 3: Reduce the fractions: $\frac{1}{2} + y = \frac{1246}{1960}$

Step 4: Subtract $\frac{1}{2}$ from both sides: $y = \frac{1246}{1960} - \frac{1}{2}$

Step 5: Convert $\frac{1}{2}$ to have a common denominator: $y = \frac{1246}{1960} - \frac{980}{1960}$

Step 6: Subtract the fractions: $y = \frac{1246 - 980}{1960}$

Step 7: Simplify: $y = \frac{266}{1960}$

Step 8: Reduce the fraction: $y = \frac{133}{980}$

So, the solution for this equation is $y = \frac{133}{980}$.

4. $\frac{60}{90} - \left(\frac{6}{90} + x\right) = \frac{29}{90}$