Question

(2 1/2 × 8 + 3 1/4 × 4) × 1 7/33

Answer 1

Відповідь:

40

Покрокове пояснення:

$(2\frac{1}{2} *8+3\frac{1}{4} *4)*1\frac{7}{33}$=$(\frac{5}{2} *\frac{8}{1} +\frac{13}{4} *\frac{4}{1}) *\frac{40}{33}$=$(\frac{5}{1} *\frac{4}{1} +\frac{13}{1} *\frac{1}{1} )*\frac{40}{33} =$$(5*4+13*1)*\frac{40}{33} =\(20+13)*\frac{40}{33}=$$33*\frac{40}{33}=\frac{33}{1}*\frac{40}{33}=\frac{1}{1} *\frac{40}{1} =\frac{40}{1} =40$

Answer 2

1) $2 \frac{1}{2} \times 8 = \frac{5}{2} \times \frac{8}{1} = \frac{40}{2} = 20$

2) $3 \frac{1}{4} \times 4 = \frac{13}{4} \times \frac{4}{1} = \frac{52}{4} = 13$

3) $20 + 13 = 33$

4) $33 \times 1 \frac{7}{33} = \frac{33}{1} \times \frac{40}{33} = \frac{1}{1} \times \frac{40}{1} = 40$

Ответ: 40

Answer 3

To solve the expression (2 1/2 × 8 + 3 1/4 × 4) × 1 7/33, we need to simplify it step by step.

First, let's convert the mixed numbers into improper fractions: 2 1/2 = 5/2 3 1/4 = 13/4 1 7/33 = 40/33

Now, we can substitute the values and simplify the expression:

(5/2 × 8 + 13/4 × 4) × 40/33

Next, we perform the multiplications within the parentheses:

(40/2 + 52/4) × 40/33 (20 + 13) × 40/33 33 × 40/33

Finally, we can cancel out the common factor of 33:

40

Therefore, the result of the expression (2 1/2 × 8 + 3 1/4 × 4) × 1 7/33 is 40.