Question

717b -84b+88c 564b+(a-b)×26 (d+c)×25+34d (d+c)×34-42d a=6 b=2 c=5 d=7

Answer 1

717b - 84b + 88c = 633b + 88c

b = 2 и c = 5

633 * 2 + 88 * 5 = 1266 + 440 = 1706

(d + c) * 25 + 34d = 25d + 25c + 34d = 59d + 25c

d = 7 и c = 5

59 * 7 + 25 * 5 = 413 + 125 = 538

564b + (a - b) * 26 = 564b + 26a - 26b = 538b + 26a

b = 2 и a = 6

538 * 2 + 26 * 6 = 1076 + 156 = 1232

(d + c) * 34 - 42d = 34d + 34c - 42d = 34c - 8d

c = 5 и d = 7

34 * 5 - 8 * 7 = 170 - 56 = 114

Answer 2

Let's calculate the given expression using the provided values for a, b, c, and d:

1. 717b - 84b + 88c: Substitute b = 2 and c = 5. = (717 * 2) - (84 * 2) + (88 * 5) = 1434 - 168 + 440 = 1706

2. 564b + (a - b) × 26: Substitute a = 6 and b = 2. = (564 * 2) + (6 - 2) × 26 = 1128 + 4 × 26 = 1128 + 104 = 1232

3. (d + c) × 25 + 34d: Substitute c = 5 and d = 7. = (7 + 5) × 25 + 34 * 7 = 12 × 25 + 238 = 300 + 238 = 538

4. (d + c) × 34 - 42d: Substitute c = 5 and d = 7. = (7 + 5) × 34 - 42 * 7 = 12 × 34 - 294 = 408 - 294 = 114

So, the calculated values are: 717b - 84b + 88c = 1706 564b + (a - b) × 26 = 1232 (d + c) × 25 + 34d = 538 (d + c) × 34 - 42d = 114